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Answer :
Final answer:
The molarity of a solution can be determined by dividing the amount of solute in moles by the volume of the solution in liters. For a solution with 39.1 mg of NaCl in 107.3 mL of solution, the molarity is approximately 6.24 x 10^-3 M.
Explanation:
To determine the molarity of a solution, you need to know the amount of solute in moles and the volume of solution in liters. In this case, we're told that there is 39.1 mg of NaCl (sodium chloride) in 107.3 mL of solution. Molarity (M) is defined as moles of solute per liter of solution.
First, we need to convert the mass of NaCl in milligrams to grams by dividing by 1000: 39.1 mg = 0.0391 g. Next, we can convert grams to moles. The molar mass of NaCl (the amount in grams that equals one mole) is approximately 58.44 g. So, we divide the mass of NaCl by its molar mass to get moles: 0.0391 g ÷ 58.44 g/mol = 0.000669 mol NaCl.
We also need to convert the volume of the solution from milliliters to liters by dividing by 1000: 107.3 mL = 0.1073 L. Finally, we calculate the molarity by dividing the moles of solute by the liters of solution: M = 0.000669 mol ÷ 0.1073 L = 0.00624 M or 6.24 x 10^-3 M.
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