Thank you for visiting The reaction is second order in A When A â 0 100 M the reaction is 20 0 complete in 35 9 minutes Calculate the. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
To find the rate constant for a second-order reaction, we use the rate law expression. For [A]0 = 0.100 M and 20% completion in 35.9 minutes, the rate constant is found to be 6.96 x 10^-2 L/min·mol, which matches answer choice A.
To calculate the rate constant for a reaction that is second order in A, we need to use the second-order rate law expression: 1/[A] = kt + 1/[A]0
Where [A] is the concentration of reactant A at time t, [A]0 is the initial concentration of A, k is the rate constant, and t is the time.
Given that [A]0 = 0.100 M and the reaction is 20.0% complete in 35.9 minutes, the concentration [A] can be found with the following: [A] = [A]0 - 0.20 * [A]0. Thus:
[A] = 0.100 M - 0.20 * 0.100 M = 0.100 M - 0.020 M = 0.080 M
Now we can plug in the values to the second-order rate law expression and solve for the rate constant k:
1/0.080 M = k * 35.9 min + 1/0.100 M
12.5 L/mol = k * 35.9 min + 10 L/mol
2.5 L/mol = k * 35.9 min
k = (2.5 L/mol) / (35.9 min)
k = 0.0696 L/min·mol
The rate constant is therefore 6.96 x 10^-2 L/min·mol, which corresponds to answer choice A.
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