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The atomic mass of potassium is 39.1. What is the mass of [tex]$6.02 \times 10^{23}$[/tex] atoms of potassium?

A. 39.1 mg
B. 39.1 g
C. 39.1 kg
D. [tex]$6.02 \times 39.1$[/tex] mg
E. [tex]$6.02 \times 39.1$[/tex] g

Answer :

We are given that the atomic mass of potassium is [tex]$39.1$[/tex]. This value represents the mass in grams of one mole of potassium atoms. One mole of any substance contains [tex]$6.02 \times 10^{23}$[/tex] atoms.

Since we have exactly [tex]$6.02 \times 10^{23}$[/tex] atoms, which is one mole, the mass is simply the atomic mass in grams. Therefore, the mass of [tex]$6.02 \times 10^{23}$[/tex] atoms of potassium is:

[tex]$$
39.1 \text{ grams}
$$[/tex]

Thus, the correct answer is option B.

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