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Answer :
Final answer:
To make a 0.183 M aqueous solution of potassium sulfate using a 500 mL volumetric flask, you need to add approximately 16.0 grams of solid potassium sulfate.
Explanation:
To calculate the amount of solid potassium sulfate needed to make a 0.183 M aqueous solution, we can use the relationship between moles, concentration, and volume.
Now the formula used for calculating moles is Moles = Concentration x Volume.
Given: concentration = 0.183 M and volume = 0.5 L,
Moles = 0.183 M x 0.5 L = 0.0915 mol.
Potassium sulfate has a molar mass of 174.2592 g/mol.
Mass = moles x molar mass = 0.0915 mol x 174.2592 g/mol = 15.96532 g.
Rounding to three significant figures, the solid potassium sulfate needed is approximately 16.0 grams.
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