Thank you for visiting A rifle is aimed horizontally at a target 116 feet away The bullet hits the target 1 60 cm below the aiming point Determine the. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Final answer:
By treating the bullet trajectory as a projectile motion problem, we determine that the speed of the bullet when it emerges from the rifle is approximately 620 m/s.
Explanation:
The subject of this question involves finding the speed of a bullet from a rifle given certain information about its trajectory. To determine the speed, we must utilize physics principles.
In this case, the bullet was aimed horizontally and hit the target 1.60 cm below the aimed point. This something was due to the force of gravity acting on the bullet the moment it left the rifle. We will treat this as a projectile motion problem, ignoring air resistance.
Knowing the acceleration due to gravity is 9.81 m/s^2 and the vertical distance is 1.60 cm (or 0.016 m), we can find the time it took for the bullet to hit the target using the equation for vertical motion h = 0.5*g*t^2. From this equation we can find out that t = sqrt((2*h)/g) = sqrt((2*0.016 m) / 9.81 m/s^2) = 0.057 s.
The horizontal distance covered by the bullet during this time period would be the distance to the target which is 116 feet (or 35.36 m). Since horizontal speed (velocity) is equal to horizontal distance/time, we can calculate the speed of the bullet when emerging from the rifle by dividing the horizontal distance by time. Hence, the speed v = d / t = 35.36 m / 0.057 s = 620.35 m/s or about 620 m/s.
Learn more about Projectile Motion here:
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