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Calculate the number of moles of each of the ions in the following solution:

38.2 mL of 0.659 M [tex]Al_2(SO_4)_3[/tex]

[tex]Al^{3+}[/tex]: __________ mol

[tex]SO_4^{2-}[/tex]: __________ mol

Answer :

In a solution of 38.2 mL of 0.659 M Al2(SO4)3, there are 0.050 moles of Al3+ ions and 0.075 moles of SO4 2- ions, as Al2(SO4)3 disassociates into 2 Al3+ ions and 3 SO4 2- ions in solution.

You are tasked with calculating the number of moles of Al3+ and SO42- ions in a solution of Al2(SO4)3. To begin, we need to convert the volume of the solution to liters because molarity (M) is moles/Liter. 1 L = 1000 mL, so 38.2 mL = 0.0382 L.

The molarity of Al2(SO4)3 is the number of moles of Al2(SO4)3 per liter, which means there are 0.659 moles of Al2(SO4)3 in 1 L of solution. Therefore, in 0.0382 L of solution, there are

(0.0382 L) * (0.659 moles/L) = 0.025 moles of Al2(SO4)3.

Al2(SO4)3 disassociates into 2 Al3+ ions and 3 SO42- ions in solution. Therefore, 0.025 moles of Al2(SO4)3 yields 2 * 0.025 = 0.050 moles of Al3+, and 3 * 0.025 = 0.075 moles of SO42-.

Learn more about molarity: https://brainly.com/question/2817451

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