Thank you for visiting Evaluate the expression 625 cdot sec 2 left tan 1 left frac 13 25 right right. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Let's break down the expression step by step:
### Step 1: Understanding the Expression
The expression we need to evaluate is:
[tex]\[ 625 \cdot \sec^2\left(\tan^{-1}\left(\frac{13}{25}\right) \cdot 8\pi\right) \][/tex]
However, it seems like the problem should involve finding the secant squared of a particular angle. Let's focus on evaluating:
[tex]\[ \sec^2\left(\tan^{-1}\left(\frac{13}{25}\right)\right) \][/tex]
### Step 2: Find the Angle
The expression [tex]\(\tan^{-1}\left(\frac{13}{25}\right)\)[/tex] means that we are looking for an angle whose tangent is [tex]\(\frac{13}{25}\)[/tex]. This can be thought of as:
- Opposite side of a right triangle = 13
- Adjacent side of the triangle = 25
### Step 3: Use Trigonometric Identities
Since [tex]\(\sec(\theta) = \frac{1}{\cos(\theta)}\)[/tex], we need [tex]\(\cos(\theta)\)[/tex]:
1. Find the Hypotenuse: Use the Pythagorean theorem.
[tex]\[
\text{Hypotenuse} = \sqrt{13^2 + 25^2} = \sqrt{169 + 625} = \sqrt{794}
\][/tex]
2. Calculate [tex]\(\cos(\theta)\)[/tex]:
[tex]\[
\cos(\theta) = \frac{\text{Adjacent side}}{\text{Hypotenuse}} = \frac{25}{\sqrt{794}}
\][/tex]
3. Calculate [tex]\(\sec(\theta)\)[/tex]:
[tex]\[
\sec(\theta) = \frac{1}{\cos(\theta)} = \frac{\sqrt{794}}{25}
\][/tex]
4. Calculate [tex]\(\sec^2(\theta)\)[/tex]:
[tex]\[
\sec^2(\theta) = \left(\frac{\sqrt{794}}{25}\right)^2 = \frac{794}{625}
\][/tex]
### Step 4: Multiply by 625
Finally, we multiply [tex]\(\sec^2(\theta)\)[/tex] by 625:
[tex]\[
625 \cdot \sec^2(\theta) = 625 \cdot \frac{794}{625} = 794
\][/tex]
### Conclusion
The final result of the expression is 794.0.
### Step 1: Understanding the Expression
The expression we need to evaluate is:
[tex]\[ 625 \cdot \sec^2\left(\tan^{-1}\left(\frac{13}{25}\right) \cdot 8\pi\right) \][/tex]
However, it seems like the problem should involve finding the secant squared of a particular angle. Let's focus on evaluating:
[tex]\[ \sec^2\left(\tan^{-1}\left(\frac{13}{25}\right)\right) \][/tex]
### Step 2: Find the Angle
The expression [tex]\(\tan^{-1}\left(\frac{13}{25}\right)\)[/tex] means that we are looking for an angle whose tangent is [tex]\(\frac{13}{25}\)[/tex]. This can be thought of as:
- Opposite side of a right triangle = 13
- Adjacent side of the triangle = 25
### Step 3: Use Trigonometric Identities
Since [tex]\(\sec(\theta) = \frac{1}{\cos(\theta)}\)[/tex], we need [tex]\(\cos(\theta)\)[/tex]:
1. Find the Hypotenuse: Use the Pythagorean theorem.
[tex]\[
\text{Hypotenuse} = \sqrt{13^2 + 25^2} = \sqrt{169 + 625} = \sqrt{794}
\][/tex]
2. Calculate [tex]\(\cos(\theta)\)[/tex]:
[tex]\[
\cos(\theta) = \frac{\text{Adjacent side}}{\text{Hypotenuse}} = \frac{25}{\sqrt{794}}
\][/tex]
3. Calculate [tex]\(\sec(\theta)\)[/tex]:
[tex]\[
\sec(\theta) = \frac{1}{\cos(\theta)} = \frac{\sqrt{794}}{25}
\][/tex]
4. Calculate [tex]\(\sec^2(\theta)\)[/tex]:
[tex]\[
\sec^2(\theta) = \left(\frac{\sqrt{794}}{25}\right)^2 = \frac{794}{625}
\][/tex]
### Step 4: Multiply by 625
Finally, we multiply [tex]\(\sec^2(\theta)\)[/tex] by 625:
[tex]\[
625 \cdot \sec^2(\theta) = 625 \cdot \frac{794}{625} = 794
\][/tex]
### Conclusion
The final result of the expression is 794.0.
Thank you for reading the article Evaluate the expression 625 cdot sec 2 left tan 1 left frac 13 25 right right. We hope the information provided is useful and helps you understand this topic better. Feel free to explore more helpful content on our website!
- You are operating a recreational vessel less than 39 4 feet long on federally controlled waters Which of the following is a legal sound device
- Which step should a food worker complete to prevent cross contact when preparing and serving an allergen free meal A Clean and sanitize all surfaces
- For one month Siera calculated her hometown s average high temperature in degrees Fahrenheit She wants to convert that temperature from degrees Fahrenheit to degrees
Rewritten by : Jeany