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Answer :
The molarity of the solution formed by dissolving 97.7 g of LiBr in enough water to yield 750.0 mL of solution is 1.5 M option (b).
To determine the molarity of a solution, we need to know the amount of solute (in moles) and the volume of the solution (in liters). In this case, we are given the mass of the solute (97.7 g) and the volume of the solution (750.0 mL).
First, we need to convert the volume from milliliters to liters. Since there are 1000 mL in 1 L, the volume of the solution is 0.750 L.
Next, we need to calculate the number of moles of the solute. To do this, we divide the mass of the solute by its molar mass. The molar mass of LiBr is 86.845 g/mol.
Number of moles = mass / molar mass
Number of moles = 97.7 g / 86.845 g/mol
Number of moles = 1.125 mol
Now we can calculate the molarity of the solution using the formula:
Molarity (M) = moles of solute / volume of solution (in L)
Molarity = 1.125 mol / 0.750 L
Molarity = 1.5 M
Therefore, the molarity of the solution formed by dissolving 97.7 g of LiBr in enough water to yield 750.0 mL of solution is 1.5 M option (b).
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To determine the molarity of a solution, you need to calculate the number of moles of the solute and then divide it by the volume of the solution in liters.
Given:
Mass of solute (libr) = 97.7 g
Volume of solution = 750.0 ml
= 0.7500 L
First, calculate the number of moles of libr (assuming it is the solute):
Molar mass of libr = 84.09 g/mol (approximate)
Number of moles = Mass / Molar mass
Number of moles = 97.7 g / 84.09 g/mol
Next, calculate the molarity using the formula:
Molarity (M) = Number of moles / Volume of solution (in liters)
Molarity = Number of moles / 0.7500 L
Now, let's perform the calculations:
Number of moles = 97.7 g / 84.09 g/mol ≈ 1.162 mol
Molarity = 1.162 mol / 0.7500 L ≈ 1.549 M
Therefore, the molarity of the solution formed by dissolving 97.7 g of libr in enough water to yield 750.0 ml of solution is approximately 1.549 M.
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