Thank you for visiting A park recreation manager wants to reshape a square sandbox The new sandbox will have one side 4 feet longer and the adjacent side 5. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
The dimensions of the original sandbox was 2 ft X 2 ft..
Let, The original has a length of Xft and a width of Xft
The area of original sandbox is X^2 ft^2
As per given statement,
The new sandbox would have a length of (X+4)ft and a width of (X+5)ft
So, the area of new sand box would be: (X+4)(X+5) ft^2
Given, the area of new sandbox will be 38 square feet greater than the area of the original sandbox.
so,
X^2+38 = (X+4)(X+5)
or, X^2+38 = X^2 + 9X + 20
Eliminating X^2 from both side
0r, 9X+ 20 = 38
0r, 9X = 18
0r, X = 18/9 = 2
So, we assumes that the original has a length of Xft and a width of Xft
then the dimensions of the original sandbox was 2 ft by 2 ft.
To know more about length and width related problems here:
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