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A hunter shoots his rifle at an angle of 27.2 degrees above the horizontal. He is holding the rifle so that the muzzle of the rifle is 2.00 m above the ground. The muzzle velocity of the rifle is 412 m/s. What is the bullet's range (in meters)?

Answer :

For the hunter holding his rifle so that they muzzle of the rifle is 2.00 m above the ground and who shoots his rifle at an angle of 27.2 degrees above the horizontal, the bullet's range is 14507.92 meters.

What is range in projectile?

The range of the projectile is the displacement in the horizontal direction. The range has no acceleration in this direction since gravity only acts vertically.

From the question, the parameters given are:

angle = 27.2 degrees

muzzle velocity= 412m/s

vertical distance of muzzle above the ground = 2.0 m

To calculate the range, we use the formula :

Range = U² sin2∅/ g

where g = 9.81 (acceleration due to gravity)

Substituting in the formula, we have

Range = U² sin2∅/ g

Range = (412)² sin(2* 27.2)/ 9.81

Range = 14507.92 meters

The maximum horizontal distance covered by any projectile is called the range and can be calculated using the formula :

Range = U² sin2∅/ g

where u= velocity

∅ = angle

g= acceleration due to gravity

The range of a projectile is the horizontal distance the projectile travels from the time it is launched to the time it comes back down to the same height at which it is launched.

Therefore, the horizontal distance is determined by the initial velocity, and the time interval during which the projectile stays in the air, which therefore also determined by the initial velocity.

Learn more about range at:

https://brainly.com/question/1045262

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Rewritten by : Jeany