Thank you for visiting A 38 2 kg crate rests on a horizontal floor and a 61 1 kg person is standing on the crate Determine the magnitude of. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
The magnitude of the normal force that the floor exerts on the crate is 973.14 N. The magnitude of the normal force that the crate exerts on the person is 599.78 N.
a) The force exerted by the floor on the crate can be calculated by using Newton’s third law of motion that states that “for every action, there is an equal and opposite reaction.” Therefore, the magnitude of the normal force that the floor exerts on the crate is equal and opposite to the weight of the crate and the person.
Here, the weight of the crate and the person is the force of gravity acting on them and can be calculated as:
mass (m) = 38.2 + 61.1 = 99.3 kg
Weight = mass × gravitational acceleration (g)
= 99.3 × 9.8
= 973.14 N
Therefore, the magnitude of the normal force that the floor exerts on the crate is 973.14 N.
(b) The magnitude of the normal force that the crate exerts on the person is equal and opposite to the force of gravity acting on the person. The force of gravity acting on the person can be calculated as:
Weight of the person = mass × gravitational acceleration (g)
= 61.1 × 9.8
= 599.78 N
Therefore, the magnitude of the normal force that the crate exerts on the person is 599.78 N.
Learn more about the Newton’s third law of motion from the given link-
https://brainly.com/question/25998091
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Rewritten by : Jeany
