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Question 22. If 38.2 mL of 0.163 M potassium hydroxide react with 25.0 mL of 0.134

M sulfuric acid solution, how many grams of potassium sulfate can be

formed?

Answer :

Final answer:

The mass of potassium sulfate formed is 0.163 grams.

Explanation:

To calculate the mass of potassium sulfate formed, we need to follow these steps:

  1. Write the balanced equation for the reaction between potassium hydroxide (KOH) and sulfuric acid (H2SO4):
  2. 2 KOH + H2SO4 -> K2SO4 + 2 H2O
  3. Calculate the number of moles of potassium hydroxide (KOH) using the given volume and concentration:
  4. moles of KOH = volume of KOH (L) x concentration of KOH (M)
  5. Calculate the number of moles of sulfuric acid (H2SO4) using the given volume and concentration:
  6. moles of H2SO4 = volume of H2SO4 (L) x concentration of H2SO4 (M)
  7. Use the balanced equation to determine the mole ratio between KOH and K2SO4:
  8. 2 moles of KOH react to form 1 mole of K2SO4
  9. Calculate the number of moles of K2SO4 formed:
  10. moles of K2SO4 = (moles of KOH) / 2
  11. Convert the moles of K2SO4 to grams using the molar mass of K2SO4:
  12. mass of K2SO4 (g) = moles of K2SO4 x molar mass of K2SO4

Learn more about calculating the mass of a product formed in a chemical reaction here:

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