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Answer :
Final answer:
To prepare a 250.0 mL solution of 0.50 M Kâ‚‚CrOâ‚„, 24.3 grams of Kâ‚‚CrOâ‚„ are needed, which corresponds to answer option A. Therefore the correct answer is A) 24.3 g.
Explanation:
The question is asking for the mass of Kâ‚‚CrOâ‚„ (potassium chromate) needed to prepare a 250.0 mL solution with a molarity of 0.50 M. To calculate this, use the molarity equation, M = moles/L, where M is molarity, moles is the amount of substance in moles, and L is the volume of solution in liters.
Hence, moles = M × L. After calculating the number of moles required, the mass of Kâ‚‚CrOâ‚„ can be determined by multiplying the number of moles by the molar mass (194.2 g/mol).
First, convert 250.0 mL to liters: 250.0 mL = 0.2500 L. Next, calculate the moles needed: moles = 0.50 M × 0.2500 L = 0.1250 mol. Finally, find the mass: mass = 0.1250 mol × 194.2 g/mol = 24.3 g.
Thus, the correct answer is: A) 24.3 g.
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