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Answer :
The pressure for 1.70 mol of gas in a 9.00 L container at 45.0°C is approximately 72.4 psi.
To find the pressure, we use the Ideal Gas Law: PV = nRT.
Here's the step-by-step calculation:
- Convert 45.0°C to Kelvin: 45.0 + 273.15 = 318.15 K
- Use the Ideal Gas Law with R = 0.0821 L atm/(K mol): P = (nRT) / V
- Substitute the values: P = (1.70 mol * 0.0821 L atm/(K mol) * 318.15 K) / 9.00 L
- This gives: P ≈ 4.93 atm
- Convert atm to psi using 1 atm = 14.7 psi: 4.93 atm * 14.7 psi/atm ≈ 72.4 psi
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