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A 30% efficient heat engine wastes 1200 J of energy in one minute of operation. How much work can this heat engine do during that one minute?

A. 400 J
B. 3600 J
C. 800 J
D. 2400 J

Answer :

Final answer:

To find the work done by a 30% efficient heat engine that wastes 1200 J of energy in one minute of operation, multiply the efficiency by the total energy input. The correct work done by the engine in one minute is 360 J, so the correct option is b.

Explanation:

To find the work done by a 30% efficient heat engine that wastes 1200 J of energy in one minute of operation, multiply the efficiency by the total energy input. A 30% efficient heat engine wastes 1200 J of energy in one minute of operation.

To find the work done, we first need to calculate the total energy input. Since the engine is 30% efficient, it converts 30% of the input energy into work. Therefore, work done = Efficiency * Total Energy Input. Given that the total energy input is 1200 J and the efficiency is 30%, Work done = 0.30 * 1200 J = 360 J. Therefore, the correct option is b) 3600 J.

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Rewritten by : Jeany

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