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ABCD is a square. Given that \(\angle AEB = 55^\circ\), calculate \(\hat{F}_1\).

Answer :

The angle AFE is 80 degrees in the quadrilateral ABCD.

Given that ABCD is a quadrilateral.

Angle AEB = 55 degrees.

In the quadrilateral AEF forms a triangle.

Angle AEF=55 degrees.

The angles AEB and AEF are corresponding angles.

AC is a diagonal so ∠EAF = 45 degrees.

On triangle AEF,

∠AFE = 180-∠EAF-∠AEF

=180-45-55

=80

Hence, the angle AFE is 80 degrees.

To learn more on Triangles click:

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