Thank you for visiting How much heat is required to melt 39 4 g of ice at tex 0 circ C tex The heat of fusion for water is. This page is designed to guide you through key points and clear explanations related to the topic at hand. We aim to make your learning experience smooth, insightful, and informative. Dive in and discover the answers you're looking for!
Answer :
Specific heat capacity of a substance is the amount of heat required to raise the temperature by one degree Celsius of one gram of a substance. Therefore, 13.12KJ of heat is required to melt 39.4 g of ice at (0 ∘C ).
What is Enthalpy?
Enthalpy term is basically used in thermodynamics to show the overall energy that a matter have. Mathematically, Enthalpy is directly proportional to specific heat capacity of a substances.
Mathematically,
q = n ×ΔH
where
q = amount of heat= ?
n = no of moles
ΔH = enthalpy ( 6.02 kJ/ mol)
n = w / M.M
w = given mass =39.4g
M.M = molar mass ( molar mass of water)=18g/mol
n =39.4/ 18
=2.18
Substituting all the given values, we get
q = n ×ΔH
= 2.18 ×6.02
= 12.401 kJ
=13.12KJ
Therefore, 13.12KJ of heat is required to melt 39.4 g of ice at (0 ∘C ).
To know more about enthalpy, here:
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