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A diver bounces straight up from a diving board, avoiding the diving board on the way down, and falls feet first into a pool. She starts with a velocity of 3.00 m/s, and her takeoff point is 1.70 m above the pool.

(a) What is her highest point (in m) above the board?
______ m

(b) How long a time (in s) are her feet in the air?
______ s

(c) What is her velocity (in m/s) when her feet hit the water? (Assume the positive direction is upward. Indicate the direction with the sign of your answer.)
______ m/s

Answer :

Final answer:

The highest point above the board is 0.9184 m. Her feet are in the air for 0.612 seconds. Her velocity when her feet hit the water is -2.98 m/s.

Explanation:

To find the highest point above the board, we can use the equation for vertical displacement. The initial velocity is 3.00 m/s and the acceleration due to gravity is -9.8 m/s^2. Plugging these values into the equation, we get:

Δy = (vi^2 - vf^2) / (2a)

Δy = (3.00^2 - 0) / (2*(-9.8))

Δy = 0.9184 m

So the highest point above the board is 0.9184 m.

To find the time her feet are in the air, we can use the equation for time of flight:

t_f = (2 * vi) / a

t_f = (2 * 3.00) / 9.8

t_f = 0.612 s

Therefore, her feet are in the air for 0.612 seconds.

When her feet hit the water, her velocity will be negative since the positive direction is upward.

To find this velocity, we can use the equation:

vf = vi + at

vf = 3.00 + (-9.8 * 0.612)

vf = -2.98 m/s

So her velocity when her feet hit the water is -2.98 m/s, indicating that she is moving downward.

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Rewritten by : Jeany