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Answer :
Final answer:
The pOH of a solution with [OH-] = 2.0 × 10-² is approximately -0.30.
Explanation:
The pOH of a solution can be calculated using the formula pOH = -log[OH-]. In this case, we are given [OH-] = 2.0 × 10-².
So, pOH = -log(2.0 × 10-²) = -log(2.0) - (-log(10²)) = -log(2.0) - (-2)
Simplifying further, pOH = - 0.301 = -0.30 (rounded to two decimal places).
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